x^2+5/4=x

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Solution for x^2+5/4=x equation: 



x^2+5/4=x

We move all terms to the left:

x^2+5/4-(x)=0

We add all the numbers together, and all the variables

x^2-1x+5/4=0

We multiply all the terms by the denominator


x^2*4-1x*4+5=0

Wy multiply elements

4x^2-4x+5=0

a = 4; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·4·5
Δ = -64
Delta is less than zero, so there is no solution for the equation

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